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Q.

A heat engine has an efficiency η.Temperatures of source and sink are each decreased by  100K.The efficiency of the engine 

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a

increases

b

decreases

c

remains the same

d

becomes 1

answer is A.

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Detailed Solution

η=1-T2T1    =T1-T2T1

When, T1 and T2 both are decreased by 100 K each T1-T2  stays constant, T1 decreases.

η increases.

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