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A heat source at $T = 10^{3} K$ is connected to another heat reservoir at $T = 10^{2} K$ by a copper slab which is 1 m thick. Given that the thermal conductivity of copper is $0.1 W K^{- 1} m^{- 1},$ the energy flux through it in the steady state is

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$90 W m^{- 2}$

$65 W m^{- 2}$

$120 W m^{- 2}$

answer is A.

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Detailed Solution

Energy Flux, $\frac{θ}{A t} = \frac{k (θ_{1} - θ_{2})}{l}$

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