A heated body emits radiation which has maximum intensity near the frequency v0. The emissivity of the material is 0.5. If the absolute temperature of the body is doubled

A) λmT=constantTv=constantTv0=2tv⇒v=2v0(c) Q=σAeT4Q1=σAe(2T)4=16Q

A heated body emits radiation which has maximum intensity near the frequency v0. The emissivity of the material is 0.5. If the absolute temperature of the body is doubled

A) λmT=constantTv=constantTv0=2tv⇒v=2v0(c) Q=σAeT4Q1=σAe(2T)4=16Q

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A heated body emits radiation which has maximum intensity near the frequency v₀. The emissivity of the material is 0.5. If the absolute temperature of the body is doubled

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the maximum intensity of radiation will be near the frequency 2v₀

the maximum intensity of radiation will be near the frequency v₀/2

the total energy emitted will increase by a factor of 16

the total energy emitted will increase by a factor of 8

answer is A, C.

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Detailed Solution

A) $λ m T = c o n s \tan t$
$\frac{T}{v} = c o n s \tan t$
$\frac{T}{v_{0}} = \frac{2 t}{v} \Rightarrow v = 2 v_{0}$
(c) $Q = σ A e T^{4}$
$Q^{1} = σ A e {(2 T)}^{4} = 16 Q$

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A heated body emits radiation which has maximum intensity near the frequency v0. The emissivity of the material is 0.5. If the absolute temperature of the body is doubled

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A heated body emits radiation which has maximum intensity near the frequency v₀. The emissivity of the material is 0.5. If the absolute temperature of the body is doubled