A heavy block kept on a frictionless surface is in equilibrium and being pulled by two ropes of equal mass m. At t = 0, the force on the left rope is withdrawn but the force on the right end continues to act. Let F₁ and F₂ be the magnitudes of the forces by the right rope and the left rope on the block respectively.

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F₁ < F, F₂ = F for t < 0

F₁ = F, F₂ < F for t < 0

F₁ = F₂ = F for t < 0

F₁ = F₂ = F + mg for t < 0

answer is A.

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Detailed Solution

For t<0 , the block is in equilibrium ,

.: F₁ - F₂ = 0 ⇒ F₁ - F₂

So option - (1) is right.

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