A heavy load  W is supported on a platform of area  S by applying a force  F on a small piston of area $S/10$.  The value of  F for equilibrium is $\left(x<<H\right)$

According to Pascal’s law the pressure at point P below the lower piston inside the liquid  $=\frac{\text{W}}{S}+\rho gH$       $\left(x<<H\right)$
The pressure caused by the force  ‘F’ is  $=\frac{F}{\left(\frac{S}{10}\right)}=\frac{10F}{S}$
As the liquid is at equilibrium  $\frac{\text{W}}{S}+\rho gH=\frac{10F}{S}$
$\Rightarrow 10F=\text{W}+\rho gHS$
$\therefore F=\frac{\text{W}+\rho gHS}{10}$
Therefore, the correct answer is (B)