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A heavy nucleus having mass number 200 gets disintegrated into smaller fragments of mass number 80 and 120. If binding energy per nucleon for parent atom is 6.5 MeV and for daughter nuclei are 7 MeV and 8 MeV respectively and the energy released in the decay is given by X x 10⁵ eV , then X will be

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answer is 2200.

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Detailed Solution

$Reaction : 200_{x} \to 80_{Y} + 120_{z} B . E \to 6.5 7 8$
Energy released ${=80×7+120×8−200×6.5=220MeV=2200×10}^{5} eV$

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