A heavy nucleus having mass number 200 gets disintegrated into small fragments of mass number 80 and 120. If binding energy per nucleon for parent atom is 6.5 MeV and for daughter nuclei is 7 MeV and 8 MeV respectively, the energy released in the decay will be $x \times 10^{5} eV$ , then calculate the value of $x$ .

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answer is 2200.

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Detailed Solution

$_{}^{200} X \to_{}^{80} Y +_{}^{120} Z$

$So, energy released is$

$\begin{array}{l} Δ E = 80 \times 7 + 120 \times 8 - 200 \times 6.5 \\ Δ E = (560 + 960) - 1300 \\ Δ E = 220 \times 10^{6} eV \\ Δ E = 2200 \times 10^{5} eV \end{array}$

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