A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5 cm. Find the outer curved surface area of the bowl.

Given that, the inner radius = 5cm and the thickness of the bowl = 0.25 cm

Outer radius = 5 + 0.25 = 5.25 cm

We know that the formula for CSA of hemispherical bowl = 2πr²

Using formula,

= 2 × (22/7) × (5.25)² 

= 173.25 cm²

Hence, the outer CSA of the bowl is 173.25 cm².