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Q.

A hemispherical bowl is made of steel, 0.25 cm thick. The inner radius of the bowl is 5 cm. Find the outer curved surface area of the bowl.

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Detailed Solution

Given that, the inner radius = 5cm and the thickness of the bowl = 0.25 cm

Outer radius = 5 + 0.25 = 5.25 cm

We know that the formula for CSA of hemispherical bowl = 2πr2

Using formula,

= 2 × (22/7) × (5.25)2 

= 173.25 cm2

Hence, the outer CSA of the bowl is 173.25 cm2.

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