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A hemispherical bowl made of brass has an inner diameter of 10.5cm. Find the cost of tin planting it on the inside at the rate of 16 per 100 cm2.

Chapter/Topic: Surface Areas and Volumes

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17.72 Rs

27.72 Rs

37.72 Rs

20.72 Rs

answer is B.

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Detailed Solution

d = 10.5cm r =

\frac{10.5}{2}

= 5.25

We can take any radius from point O to touch the surface of the hemisphere.
Curved surface area of hemisphere=2πr2= 2π(5.25)2 = 173.25 cm2
Cost of tin plating 100 cm2= 16Rs
Cost of tin plating 1 cm2=

\frac{16}{100}

Rs
Cost of tin plating 173.25 cm2=

\frac{16}{100}

×173.25= 27.72Rs

Cost of tin plating= 27.72 Rs.
Hence, Option (2) is the correct answer.

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