A hemispherical tank is made up of an iron sheet 1 cm thick. If the inner radius is 1 m, then find the volume of the iron used to make the tank.

Given: Inner Radius (r₁ ) = 1 m and Outer Radius (r₂) = 1.01 m

Here we will use the formula of volume of hemisphere  = (2/3) π(R³– r³)

Substituting the values,

Volume of the iron used in the hemispherical tank = (2/3) × (22/7) × (1.01³ – 1³)

 = 0.06348 m³.