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A heterozygous bald man is non hemophilic, married a woman who is homogenous for non bald trait and is haemophilic. What is the probability of their sons to become bald and haemophilic among the total progeny?

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Detailed Solution

Heterozygous bald, non hemophilic man produces four gametes i.e XB, Xb, YB and Yb

Homozygous non bald, hemophilic woman produces X^hb type of gamete. Crossing between them

	X^h
XB	XX^hBb	Non hemophilic and non bald daughter
Xb	XX^h bb	Non hemophilic and non bald daughter
YB	X^hYBb	Hemophilic and bald son
Yb	X^hYbb	Hemophilic and non bald son

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