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Q.

A hiker stands on the edge of a cliff 490 m above the ground and throws a stone horizontally with an initial speed of 15ms^-1 Neglecting air resistance, the speed with
which it hits the ground in ms^-1 is (g=9.8ms^-2)

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a

4.9

b

99

c

9.8

d

49

answer is B.

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Detailed Solution

$V = \sqrt{V_{x}^{2} + V_{y}^{2}}; V_{y}^{2} = 2 g h$

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