A hollow cylinder and a solid cylinder of the same mass and radius are released simultaneously from rest at the top of the same inclined plane, which will reach the ground first?

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solid cylinder

hollow cylinder

both will take the same time

it cannot be predicted.

answer is A.

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Detailed Solution

THE TIME TAKEN TO REACH THE BOTTOM IS GIVEN BY $T = \sqrt{\frac{2 L}{a}}$

a = $\frac{g \sin θ}{1 + \frac{I}{{MR}^{2}}},$ For solid cylinder I is less, so a is more, hence time taken will be less.

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