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A hollow cylinder has a charge q at it’s center. If $φ$ is the electric flux associated with the curved surface B, the flux linked with the plane surface A will be:

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$\frac{q}{ε_{0}} - ϕ$

$\frac{q}{2 ε_{0}}$

$\frac{ϕ}{3}$

$\frac{1}{2} (\frac{q}{ε_{0}} - ϕ)$

answer is A.

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Detailed Solution

$ϕ_{t o t a l} = ϕ_{A} + ϕ_{B} + ϕ_{C} = \frac{q}{\in_{0}}$

Since $ϕ_{C} = ϕ_{A}$

Hence, $ϕ_{A} = \frac{1}{2} (\frac{q}{ε_{0}} - ϕ)$

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