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Q.

A hollow cylinder having external radius 8 cm and height 10 cm has a total surface area of  338π  cm 2  . Find the thickness of the hollow metallic cylinder.


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a

2 cm  

b

3 cm  

c

4 cm  

d

5 cm   

answer is B.

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Detailed Solution

Given,
External radius 8 cm and height 10cm,
Total surface area =338πc m 2  
Let the internal radius of the hollow cylinder = r cm
Total surface area,
2πR+2πr+2π( R 2 r 2 )=38π  
=2π(Rh+rh+ R 2 r 2 )=338π(1)  
IMG_256 (10×8)+(10×r)+ (8) 2 r 2 = 338π 2π  
(80)+(10r)+64 r 2 =169 r 2 +10r=169144 r 2 +10r=25(2)  
r 2 10r+25=0  
r 2 (5+5)r+25=0 r 2 5r5r+25=0 r(r5)5(r5)=0  
(r5)=0 r=5  
Now as we know the thickness of a hollow cylinder can be obtained by subtracting the inner radius which is r from the outer radius which is R as given in the solution hint. Therefore
The thickness of the metal Question ImageWhen substituting the values ​​in the above expression
85 =3cm  
Hence, option 2 is correct.
 
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