A hollow cylinderical wire carries a current I, having inner and outer radii ‘R’ and 2R respectively. Magnetic field at a point which 3R/2 distance away from its axis is :

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$\frac{5 μ_{0} I}{9 πR}$

$\frac{2 μ_{0} I}{18 πR}$

$\frac{μ_{0} I}{36 πR}$

$\frac{5 μ_{0} I}{36 πR}$

answer is C.

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Detailed Solution

$C u r r e n t e n c l o s e d i n t h e a r e a c o n c e r n e d \frac{I}{3 R^{2}} (\frac{9 R^{2}}{4} - R^{2}) = \frac{I}{3} \frac{5}{4} = \frac{5 I}{12} \int B . d l = μ_{0} \frac{5 I}{12} B = μ_{0} \frac{5 I}{12} \frac{1}{2 π \frac{3 R}{2}} = μ_{0} \frac{5 I}{12} \frac{1}{3 π R}$

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