A hollow glass sphere of inner radius 5 cm & outer radius 10 cm is viewed as shown in figure. If refractive index of glass is 32, find distance (in cm) between A & O as seen by the observer? (Assume near normal incidence of light)

O point will appear at its original position, & for point A, refraction from outer surface1v−3/2−5=1−32−101v=120−310=−520=−14⇒v=−4 cm⇒ distance from O=10−4=6 cm

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A hollow glass sphere of inner radius 5 cm & outer radius 10 cm is viewed as shown in figure. If refractive index of glass is $\frac{3}{2},$ find distance (in cm) between A & O as seen by the observer? (Assume near normal incidence of light)

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Detailed Solution

O point will appear at its original position, & for point A, refraction from outer surface
$\frac{1}{v} - \frac{3 / 2}{- 5} = \frac{1 - \frac{3}{2}}{- 10}$
$\frac{1}{v} = \frac{1}{20} - \frac{3}{10} = \frac{- 5}{20} = - \frac{1}{4}$
$\Rightarrow v = - 4 c m \Rightarrow$ distance from $O = 10 - 4 = 6 c m$
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