A hollow hemisphere of uniform charge Q1, is found to produce same electric field at its centre of curvature as does a solid non-conducting hemisphere of uniform charge Q2, distributed uniformly over its volume. Radii of both spheres is same. The ratio Q1Q2 is

Book Online Demo

Check Your IQ

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

A hollow hemisphere of uniform charge $Q_{1}$ , is found to produce same electric field at its centre of curvature as does a solid non-conducting hemisphere of uniform charge $Q_{2}$ , distributed uniformly over its volume. Radii of both spheres is same. The ratio $\frac{Q_{1}}{Q_{2}}$ is

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

answer is 3.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

$E_{hollow} = \frac{σ}{{4ε}_{0}},σ-surface charge density$
$E_{solid} = \frac{ρ R}{{4ε}_{0}}, ρ -volume charge density$
But $E_{hollow} {=E}_{solid}$
$\Rightarrow σ = ρ R$
$\Rightarrow \frac{Q_{1}}{4 π R^{2}} = \frac{Q_{2} R}{\frac{4}{3} π R^{3}}$
$\Rightarrow \frac{Q_{1}}{Q_{2}} = 3$