Q.

A hollow spherical conductor of radius 4 cm carries a positive charge of 109×1010C. At what distance (in cm) from centre of sphere should a positive point charge of 409×1010C be placed so that the potential of the conductor becomes 75 V ? Assume potential to be zero at infinity.

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answer is 8.

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Detailed Solution

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Net potential of the sphere is

V=KQR+Kqx

75=9×109109×10-104×10-2+9×109409×10-10x

On solving 

x=8cm

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