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Q.

A hollow square-shaped tube open at both ends is made of iron. The side of internal square is 5 cm and the length of the tube is 8 cm. There is 192 cm3 of iron in this tube. Find its thickness.


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a

0

b

1

c

2

d

3 

answer is B.

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Detailed Solution

Suppose the tube's thickness = x cm.
From the given condition, side of the square's
=5+2x cm Internal volume of the tube subtracted from its exterior volume equals the amount of iron it contains.
⇒5+2x×5+2x×8-5×5×8=192 
⇒8(5+2x)2-25=192 
⇒(5+2x)2=49 
⇒5+2x=7 
⇒x=1 
So, the required thickness is 1 cm.
Thus, the correct option is 2.
 
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