Q.

A homogeneous disc with a radius 0.2m and mass 5kg rotates around an axis passing through its centre. The angular velocity of rotation of the disc as a function of times is given by the formula ω=2+6t. the tangential force applied to the rim of the disc is

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a

4N

b

3N

c

1N

d

2N

answer is C.

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Detailed Solution

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Here, r=0.2m, m=5kg As

ω=2+6t 

α=dt=6 rad/s2

τ= F×r=12mr2α F=mrα2=5×0.2×62=3N.

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A homogeneous disc with a radius 0.2m and mass 5kg rotates around an axis passing through its centre. The angular velocity of rotation of the disc as a function of times is given by the formula ω=2+6t. the tangential force applied to the rim of the disc is