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Q.

A homogeneous solid cylinder of length L (L < H2). Crosssectional area A5 is immersed such that it floats with its axis vertical at the liquid-liquid interface with length L4 in the denser liquid as shown in the fig. The lower density liquid is open to atmosphere having pressure P0. Then density D of solid is given by

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a

54d

b

45d

c

Ad

d

d5

answer is A.

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Detailed Solution

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Weight of cylinder = upthrust due to both liquids

V×D×g = (A5.34L)×d×g+(A5.L4)×2d×g

(A 5.L)D.g= ALdg4  D5 = d4  D = 54d

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