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Q.

A horizontal block A is at rest on a smooth horizontal surface. A small block B, whose mass is half of A, is placed on A at one end and project along other end with some velocity u. The coefficient of friction between blocks is µ. Then

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a

the blocks will reach a final common velocity u/3

b

the work done against friction is two-third of the initial kinetic energy of B

c

before the blocks reach a common velocity, the acceleration of A relative to B is (2/3) µg

d

before the block reach a common velocity, the acceleration of A relative to B is (3/2) µg

answer is A, B, D.

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Detailed Solution

From conservation of momentum,

 m2u=m+m2v v=u3

Work done against friction =EiEf

=12m2u2-123m2u32 =16mu2=2314mu2

Force of friction on the two blocks before the blocks reach a common velocity is as shown below, 

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a1=μg and a2=μ2g ar=32μg

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