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A horizontal force applied on a body on a rough horizontal surface produces an acceleration ‘a’. If coefficient of friction between the body & surface which is µ is reduced to µ/3, the acceleration increases by 2 units. The value of µ is

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$\frac{3}{2 g}$

$\frac{2}{3 g}$

$\frac{3}{g}$

$\frac{1}{g}$

answer is C.

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Detailed Solution

$m a = F - μ m g$

$F - \frac{μ}{3} m g = m (a + 2)$

$μ = \frac{3}{g}$

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