A horizontal jet of water coming out of a pipe of area of cross -section 20 cm2 hits a vertical wall with a velocity of 10 ms–1 and rebounds with the same speed. The force (in N ) exerted by water on the wall is,

Volume of water coming out of the pipe per sec = A×v =20×10-4×10=0.02 m3/smass of water hitting the wall per sec = m = =0.02×103=20 kg/sec force =2mvt=2×20×10=400 N

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A horizontal jet of water coming out of a pipe of area of cross -section 20 cm² hits a vertical wall with a velocity of 10 ms^–1 and rebounds with the same speed. The force (in N ) exerted by water on the wall is,

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Detailed Solution

Volume of water coming out of the pipe per sec = A×v $= 20 \times 10^{- 4} \times 10 = 0.02 m^{3} / s$

mass of water hitting the wall per sec = m = $= 0.02 \times 10^{3} = 20 kg / \sec$

$force = \frac{2 mv}{t} = 2 \times 20 \times 10 = 400 N$

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