A horizontal overhead powerline is at a height of 4m from the ground and carries a current of 100A from east to west. The magnetic field directly below it on the ground is $(μ_{0} = 4 π \times 10^{- 7} {TmA}^{- 1})$

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$2.5 \times 10^{7} T$ northward

$2.5 \times 10^{- 7} T$ southward

$5 \times 10^{- 6} T$ northward

$5 \times 10^{- 6} T$ southward

answer is D.

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Detailed Solution

By ampere’s theorem

$B = \frac{μ_{0} I}{2 π d}$

$= \frac{4 π \times 10^{- 7} \times 100}{2 π \times 4}$

$= 50 \times 10^{- 7} = 5 \times 10^{- 6}$ southward

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