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A horizontal pipe of non- uniform cross sectional area allows water to flow through it with a velocity 2m/s when pressure is 80 kpa at a point. If the velocity of flow has to be 4m/s at same other point. The pressure at that point should be

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63 k pa

74 k pa

87 k pa

53 k pa

answer is B.

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Detailed Solution

$p_{1} - p_{2} = \frac{ρ}{2} (v_{2}^{2} - v_{1}^{2})$

$= \frac{1000}{2} (4^{2} - 2^{2}) = 500 (16 - 4) = 500 \times 12 = 6000$

$80, 000 - p_{2} = 6000 \Rightarrow p_{2} = 74, 000 p a = 74 k p a$

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