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A horizontal pipe of non-uniform cross - section has water flow through it such that the velocity is $1 m s^{- 1}$ at a point where the pressure is 50 KPa. The pressure at a point where the velocity flow is $2 m s^{- 1}$ is

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1500 Pa

51500 Pa

48500 Pa

3000 Pa

answer is C.

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Detailed Solution

$P_{1} - P_{2} = \frac{ρ}{2} (v_{2}^{2} - v_{1}^{2})$

$50, 000 - P_{2} = \frac{1000}{2} (4 - 1) 50, 000 - P_{2} = 1500$

$P_{2} = 48500 p a$

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