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A horizontal ring of radius $r = \frac{1}{2} m$ , is kept in a vertical constant magnetic field 1 T. The ring is collapsed from maximum area to zero area in 1 s. Then the emf induced in the ring is

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$(π / 4) V$

1 V

$(π / 2) V$

$π V$

answer is B.

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Detailed Solution

$|e| = B \frac{d A}{d t}$

$|e| = B \frac{(A_{2} - A_{1})}{(t_{2} - t_{1})}$

$|e| = \frac{1 (\frac{π}{4} - 0)}{(1 0)}$

$e = \frac{π}{4} V$

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