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A horizontal rod of mass ‘M’ and length ‘L’ is tied to two vertical string symmetrically as shown in the figure. One of the strings at end Q is cut at t = 0 and the rod starts rotating about the other end P. Then

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At t = 0, angular accelerration of rod about P is 3g/2L.

At t = 0, accelerration of C.M. of rod is 3g/4 in downward direction.

At t = 0, tension in the string a P is Mg/4.

At t = 0, angular accelerration of rod about C.M. of rod is 3g/2L.

answer is A, B, C, D.

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Detailed Solution

$T = I α, a_{c o m} = γ_{c o m} α, H e r e M g - T_{p} = M a_{c o m}$

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