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A horizontal straight rod PQ of 2m length along east-west direction with Q on west is falling freely under gravity. If horizontal component of earths magnetic field at that place is 0.3G. The emf induced between the ends of rod at the end of 2s is (g=10ms^-2)

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120 mV, with P at higher potential

1.20 mV, with Q at higher potential

Zero

1.20 mV with P at higher potential

answer is D.

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Detailed Solution

$e = B_{H} l V = B_{H} l gt$ here t= 2 sec V=gt

and current is from Q to P and P is at higher potential.

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