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A horizontal telegraph wire 0.5 km long running east and west is a part of a circuit whose resistance is $2.5 Ω .$ The wire falls to the ground from a height of 5 m. If $g = 10.0 m / s^{2}$ and horizontal component of earth’s magnetic field is $2 \times 10^{- 5} w e b e r / m^{2},$ then the current induced in the circuit just before the wire hits the ground will be

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0.7 amp

0.04 amp

0.02 amp

0.01 amp

answer is B.

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Detailed Solution

$ε = B l v = 2 \times 10^{- 5} \times 500 \times \sqrt{2 \times 10 \times 5} = 0.1 V$

$∴ I = \frac{ε}{R} = \frac{0.1}{2.5} = 0.04 a m p$

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