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A horizontal tube of length 1 m, sealed at both ends, is completely filled with water. The tube is moving parallel to its length with constant acceleration of $5 m / s^{2}$ . Then pressure difference between its two ends is

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1.2 KPa

10 KPa

1.8 KPa

5 KPa

answer is B.

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Detailed Solution

S = cross - sectional area of the tube.

$∴$ Mass of water = sl $ρ$

$∴$ By Newton's second law,

(sl $ρ$ ) $a = p_{1} s - p_{2} s \Rightarrow p_{1} - p_{2} = ρ a l = 10^{3} \times 5 \times 1 \frac{N}{m^{2}}$

$\Rightarrow p_{1} - p_{2} = 5 K P a$

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