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Q.

A horse drinks water from a cubical container of side 1 m. The level of the stomach of horse is at 2m from the ground. Assume that all the water drunk by the horse is at a level of 2m from the ground. Then minimum work done by the horse in drinking the entire water is container is

(Take ρwater=1000kg/m3  and g=10m/s2 ) -

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a

10 kJ

b

20 kJ

c

Zero

d

15 kJ

answer is B.

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Detailed Solution

The mass of water is m=1×103kg 

Height of centre of mass of water is 12m

Height of horse from  water  surface is 1m

Total height h=1+12=1.5m

  The increase in potential energy of water is =mgh=(1×103)(10)(1.5)=15kJ

 

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