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Q.

A horse drinks water from a cubical container of side 1 m. The level of the stomach of horse is at 2m from the ground. Assume that all the water drunk by the horse is at a level of 2m from the ground. Then minimum work done by the horse in drinking the entire water is container is
(Take $ρ_{w a t e r} = 1000 k g / m^{3}$ and $g = 10 m / s^{2}$ ) -

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a

10 kJ

b

15 kJ

c

20 kJ

d

Zero

answer is B.

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Detailed Solution

The mass of water is $m = 1 \times 10^{3} k g$

Height of centre of mass of water is $\frac{1}{2} m$

Height of horse from water surface is 1m

Total height h=1+ $\frac{1}{2} = 1.5 m$

$∴$ The increase in potential energy of water is $= m g h = (1 \times 10^{3}) (10) (1.5) = 15 k J$

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A horse drinks water from a cubical container of side 1 m. The level of the stomach of horse is at 2m from the ground. Assume that all the water drunk by the horse is at a level of 2m from the ground. Then minimum work done by the horse in drinking the entire water is container is (Take ρwater=1000kg/m3 and g=10m/s2 ) -