A horse rider covers half the distance with 5 m/s speed. The remaining part of the distance was travelled with speed 10 m/s for half the time and with speed 15 m/s for other half of the time. The mean speed of the rider averaged over the whole time of motion is $\frac{50}{x}$ m/s. The value of x is:

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answer is 7.

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Detailed Solution

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In month BC
$x = d_{1} + d_{2}$
Where, $d_{1}$ and $d_{2}$ are the distance travelled with 10 m/s and 15 m/s respectively in equal time intervals $\frac{' t'}{2}$ each.

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