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A house worth Rs. 9000 is sold by Mr. A to Mr. B at a $10 %$ loss Mr. B. sells the house back Mr. A at a $10 %$ gain. Find the result of the two transactions.

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Mr. A breaks even

Mr. B gains Rs. 900

Mr. A loses Rs. 900

Mr. Aloses Rs. 810

answer is D.

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Detailed Solution

Given,
House price=9000
Loss%= 10%
Thus, Selling Price of house to

Mr. B

= cost price - loss

= (9000 - 9000 \times \frac{10}{100})

= Rs . 8100

Also, the gain%= 10%
So, selling Price of house to

Mr. A

can be calculated as,

= cost price + gain

= (8100 + 8100 \times \frac{10}{100})

= Rs 8910

So, selling price of A = Rs. 8100
Cost price of A = Rs. 8910.
Here, A loses = 8910 - 8100
loss= Rs 810 Option 4 is correct.

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