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A human patient suffering from a duodenal ulcer may show a hydrochloric acid concentration of $0.080 m o l / L$ in his gastric juice. It is possible to neutralize this acid with aluminum hydroxide, $Al {(OH)}_{3}$ , which reacts with $HCI$ according to the chemical reaction shown below:
$Al (OH)_{3} + HCl ⟶ {AlCl}_{3} + H_{2} O$
Find wt. of $Al {(OH)}_{3}$ which is required to neutralize $2 L$ $HCl$ :

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4.16 g

0.693 g

2.08 g

6.20 g

answer is D.

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Detailed Solution

$\begin{array}{l} Al (OH)_{3} + 3 HCl ⟶ {AlCl}_{3} + 3 H_{2} O \\ W_{Al ({OH}_{3}} = \frac{1}{3} \times 0.08 \times 78 \times 2 \\ \Rightarrow 4.16 g \end{array}$

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