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Q.

A hydraulic machine exerts a force of 900 N on a piston of diameter 1.80 cm the out put force is exerted on a piston of diameter 36 cm , then output force is .

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a

36×104 N

b

36×105 N

c

36×106 N

d

36×107 N

answer is A.

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Detailed Solution

F1=900  

diameter d1=1.8cm  

r1=0.9cm  

F2=?      

diameter d2=36,r2 =18cm

⇒900π×(0.9)2=Fπ×(18)2        

 F=900 × 18 × 180.9 × 0.9=36×104N

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