A hydrocarbon $A\left(C_{10}{H}_{18}\right)$ is capable of showing both enantiomerism as well as diasteromerism. Treatment of either with $HgS{O}_4/H_{2}S{O}_4$ or $B_2{H}_6/H_2{O}_2-NaOH$result in the same carbonyl compound B. Also, $\underset{C_2{H}_{5}OH\left(dry\right)}{\overset{Na}{\to }}B\underset{Zn/H_{2}O}{\overset{O_3}{\to }}C\left(C_5{H}_{10}O\right)$. C can also be obtained as one of the product in the following reaction. ${\text{I-butene+CO+H}}_{\text{2}}\stackrel{{\text{CO}}_{\text{2}}{\left(\text{CO}\right)}_{\text{8}}}{\to }\text{C+other product}$