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A hydrocarbon was found to contain $91.3 % C$ . The molecular formula of the compound is

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$C_{6} H_{6}$

$C_{7} H_{8}$

$C_{7} H_{7}$

$C_{6} H_{7}$

answer is C.

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Detailed Solution

Given that carbon is $91.3 %$ , therefore mass of carbon is $91.3 g$ .

No. of moles of C $= 91.3 / 12 = 7.608$

The remaining percentage is $8.7 %$ which belongs to H, therefore mass of H is $8.7 g$ .

No. of moles of carbon $= 8.7 / 1 = 8.7$

Ratio of moles of $C : H$ is $1 : 1.143 = 7 : 8$

The molecular formula of the compound is $C_{7} H_{8}$

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