A hydrocarbon with formula C₈H₁₈ gives one monochloro derivative. The hydrocarbon is:

${\mathrm{C}}_8{\mathrm{H}}_{18}\stackrel{{\mathrm{Cl}}_2}{\to }\mathrm{One} \mathrm{monochlorination} \mathrm{product}.$
From, the given reaction we can say that this 2,2,3,3-tetramethylbutane give only one chlorination product as chlorine is added to one of the −CH₃​ group.