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A hydrocarbon with formula C₈H₁₈ gives one monochloro derivative. The hydrocarbon is:

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n – octane

2 methyl heptane

2,2,4 – trimethylpentane

2,2,3,3-tetra methyl butane

answer is D.

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Detailed Solution

$C_{8} H_{18} \overset{{Cl}_{2}}{\to} One monochlorination product .$
From, the given reaction we can say that this 2,2,3,3-tetramethylbutane give only one chlorination product as chlorine is added to one of the −CH₃ group.

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