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A hydrocarbon X has molecular formula C₅H₁₀. X on treatment with B₂H₆ in H₂O₂/NaOH gives an optically active C₅H₁₂O which on treatment with CrO₃/HCl/ pyridine gives C₅H₁₀O which is still chiral. Which of the following can be a product of reductive ozonolysis of X?

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answer is C.

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