A hydrogen atom and a doubly ionized lithium atom are both in the second excited state. If  $L_H$ and  $L_{Li}$  respectively represent their electronic angular momenta  and  $E_H$ and  $E_{Li}$  their energies, then :

For both the atoms the second excited state corresponds to  $n=3.$ Therefore, the angular momentum for each of them is $3(h/2\pi ).$  The energy, however, is proportional to $Z^2$  where $Z$   is the atomic number and hence numerical value of energy for hydrogen is less than that for lithium.