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Q.

A hydrogen atom in ground state absorbs 10.2 eV of energy. The orbital angular momentum of the electron is increased by

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a

1.05 × 10–34Js

b

2.11  × 10–34Js

c

3.16 × 10–34Js

d

4.22 × 10–34Js

answer is A.

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Detailed Solution

→ΔE=10.2eV;n1=1,n2=2→∴ΔL=h2πn2−n1=6.6×10−342×3.14(2−1)=1.05×10−34

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