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Q.

A hydrogen atom is excited from ground state to second excited state when it absorbs a photon. The energy of the photon is

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a

$12.09 eV$

b

$12.75 eV$

c

$3.4 eV$

d

$10.2 eV$

answer is C.

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Detailed Solution

second excited state= 3rd level

energy = $13.6 (\frac{1}{1^{2}} - \frac{1}{3^{2}}) = 12.09 e V$

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