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A hydrogen atom undergoes a transition from the state $n=5$ to $n=2$ state. If the angular momentum is conserved and if the Bohr model is used to describe the atom, what must be the angular momentum of the photon that is emitted?

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$6.67 \times 10^{- 34} J s$

$2.22 \times 10^{- 34} J s$

$6.34 \times 10^{- 34} J s$

$3.17 \times 10^{- 34} J s$

answer is D.

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Detailed Solution

$L = n \frac{h}{2 π}$

$Δ L = (2 - 5) \frac{h}{2 π} = \frac{3 (6.63 \times 10^{- 34} Js)}{2 \times 3.14} = - 3.17 \times 10^{- 34} Js$

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