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A hydrogen balloon released on the moon would:

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climb up with an acceleration of 9.8 x 6 m/sec²

climb up with an acceleration of 9.8 m/sec²

neither climb nor fall

fall with an acceleration of (9 .8/6) m/sec²

answer is D.

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Detailed Solution

Upthrust force = volume ×density×g On moon surface g is decrease that is one sixth of the g on earth surface so upthrust force decrease there fore balloon on moon surface falls with an acceleration g/6 so option 4 is correct

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