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A hydrogen electrode is immersed in a solution with pH=0(HCl). By how much will the potential (reduction) change if an equivalent amount of NaOH is added to the solution. (Take pH₂ =1atm & T = 298K )

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decrease by 0.41 V

increase by 0.41 V

increase by 59 mV

decrease by 59 mV

answer is C.

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Detailed Solution

pH changes from 0 to 7
Accordingly E_red decreases by 0.059 $\log 10^{- 7} i . e . 0 .059 \times (- 7) = - 0 .41 volt$

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