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Q.

A hydrogen gas electrode is made by dipping platinum wire in a solution of HCl of pH = 10 and by passing hydrogen gas around the platinum wire at one atm pressure. The oxidation potential of electrode would be?

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a

0.059 V

b

0.59 V

c

0.118 V

d

1.18 V

answer is B.

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Detailed Solution

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Given pH of HCl solution = 10
$\begin{aligned} i.e., [{OH}^{+}] = 10^{- 10} M \\ P_{H_{2}} = 1 atm \end{aligned}$
For a hydrogen electrode,
$\begin{array}{l} H_{(aq)}^{+} + e^{-} \to \frac{1}{2} H_{2 (g)} \\ E_{cell} = \frac{0.059}{n} \log k_{c} \\ = \frac{0.059}{1} \log \frac{P_{H_{2}}}{[H^{+}]} \end{array}$
$\begin{array}{l} = 0.059 \log \frac{1}{10^{- 10}} \\ = + 0.059 (10) = + 0.59 V \end{array}$

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